Hi, here is my ocp 1z0-001 pl/sql dump(some answers may be wrong). I passed the exam with 55 score. The questions are not difficult, but you should answer the question carefully. ----------------------------------------------------------1. SCOTT FORGOT HIS PASSWORD WHILE ON VACATION WHICH COMMAND MUST BE EXECUTED TO SET A PASSWORD FOR SCOTT A. DBA MUST EXECUTE THE COMMAND ALTER USER SCOTT IDENTIFIED BY LION 2. YOU ARE UPDATING THE EMPLOYEE TABLE JANE HAS BEEN GRANTED THE SAME PRIVILAGES AS YOU ON THE EMPLOYEE TABLE YOU ASK JANE TO LOG ON TO THE DATABASE TO CHECK YOUR WORD BEFORE YOU ISSUE THE COMMIT COMMAND WHAT CAN SHE DO TO THE EMPLOYEE TABLE A. JANE CAN ACCESS THE TABLE BUT SHE CAN NOT SEE YOU CHANGES AND CAN NOT MAKE THE CHANGES TO THE ROLES THAT YOU ARE CHANGING 3. EXAMINE THE STRUCTURE OF THE STUDENT TABLE NAME NULL TYPE STUD_ID NOT NULL NUMBER(3) NAME NOT NULL VARCHAR2(25) ADDRESS VARCHAR2(50) GRADUATION DATE WHICH STATEMENT INSERT A NEW ROW INTO THE STUDENT TABLE ? A. INSERT INTO STUDENT (STUD_ID, ADDRESS, NAME, GRADUATION) VALUES (101,MAIN STREET? MITH? ?7-JAN-00?; 4. EXAMINE THE STRURE OF THE STUDENT TABLE GRADUATION COLUMN IS A FORIGN KEY COLUMN TO THE GRADUATE TABLE EXAMINE THE DATA IN THE GRAD_DATE_TABLE GRADUATION 20-JAN-1999 12-MAY-1991 19-JAN-2000 25-JAN-2000 13-JAN-2001 29-JAN-2001 WHICH UPDATE STATEMENT PRODUCES THE FOLLOWING ERROR ORA-02291 INTEGRITY CONSTRAINT (SYS-C-23) VIOLDATED PARENT KEY NOT FOUND A. UPDATE STUDENT SET NAME = MITH? GRADUATION = ?5-AUG-2000? WHERE STUD-ID = 101 5. THE VIEW EMP-VIEW IS CREATED BASED ON THE EMP TABLE AS FOLLOWS CREATE OF REPLACE VIEW EMP_VIEW AS SELECT DEPTNO, SUM(SAL) TOT_SAL, COUNT(*) NOT_EMP FROM EMP GROUP BY DEPTNO; WHAT HAPPENS WHEN THIS COMMAND IS USED ? UPDATE EMP_VIEW SET TOT_SAL = 20000 WHERE DEPTNO = 10; ANS THE BASE TABLE CANNOT BE UPDATED THROUGH THIS VIEW 6. YOU HAVE A VIEW CALLED ANN_SAL THAT IS BASED ON THE EMPLOYEE TABLE STRUCTURE ON THE ANN-SAL VIEW IS NAME NULL TYPE EMPNO NOTNULL NUMBER(4) YEARLY_SAL NUMBER(9,2) MONTHL_SAL NUMBER(9,2) WHICH STATEMENT RETRIVES ALL DATA FROM ANN_SAL VIEW ? ANS. SELECT * FROM ANN_SAL; 7. EVALUATE THIS IF STATEMENT IF V_VALUE > 100 THEN V_NEW_VALUE := 2 * V_VALUE ELSEIF V_VALUE >200 THEN V_NEW_VALUE := 3 * V_VALUE ELSEIF V_VALUE >300 THEN V_NEW_VALUE := 4 * V_VALUE ELSE V_NEW_VALUE := 4 * V_VALUE ENDIF; WHAT VALUE BE ASSIGNED TO V_NEW_VALUE IF V_VALUE = 250: ANS: 500 8. THE PLAYER TABLE CONTAINTS THESE COLUMNS ID NUMBER(9) NAME VARCHAR(2) MANAGERID NUMBER(9) IN THIS INSTANCE MANAGER ARE PLAYER AND YOU NEED TO DISPLAY A LIST OF PLAYERS EVALUATE THESE SQL STATEMENT SELECT P.NAME,M.NAME FROM PLAYER P, PLAYER M WHERE M.ID = P.MANAGERID; SELECT P.NAME,M.NAME FROM PLAYER P, PLAYER M WHERE M.MANAGERID = P.ID HOW WOULD THE RESULT DIFFER ANS: THE RESULT WILL BE SAME BUT DISPLAY WILL BE DIFFERENT. 9. HOW WOULD YOU DECLARE A PLSQL TABLE OF RECORDS TO HOLD THE ROWS SELECTED FROM THE EMP TABLE? DECLARE TYPE EMP_TABLE IS TABLE OF EMP%ROWTYPE INDEX BY BINARY INTEGER E EMP_TABLE EMP_TABLE_TYPE; YOU WANT TO CREATE A CURSOR THAT CAN BE USED SEVERAL TIMES IN A BLOCK. SELECTING A DIFFERENT ACTIVE SET EACH TIME THAT IT IS OPENED WHICH TYPE OF CURSOR DO YOU CREATE ANS: A CURSOR THAT USE PARAMETERS 10. WHICH STATEMENT IS TRUE WHEN WRITING A CURSOR FOR LOOP ? ANS: YOU DO NOT EXPLICITY OPEN, FETCH OR CLOSE A CURSOR WITHIN A CURSOR FOR LOOP. 11. THE STRUCTURE OF THE DEPT TABLE NAME NULL TYPE DEPTNO NOTNULL NUMBER(25) DNAME VARCHAR2(14) LOC VARCHAR2(5) EXAMINE THE CODE DECLARE DEPT_REC DEPT%ROWTYPE BEGIN SELECT * INTO DEPT_REC FROM DEPT WHERE DEPTNO = 10; END WHICH PL/SQL STATEMENT DISPLAYS THE LOCATION OF SELECTED DEPARTMENT. ANS: DBMS_OUTPUT.PUT_LINE(DEPT_REC_LOC); 12. WHICH STATEMENT ABOUT IMPLICT CURSOR IS TRUE ? IMPLICT CURSORT ARE DECLARED IMPLICITY FOR ALL THE DML AND SELECT STATEMENTS 13. EVALUATE THIS PL/SQL BLOCK DECLARE V_RESULT NUMBER(2) BEGIN DELETE FROM EMPLOYEE WHERE DEP_ID IN(10,20,30); V_RESULT:= SQL%ROWCOUNT; COMMIT END; WHAT WILL BE THE VALUE OF V_RESULT IF NO ROWS ARE DELETED; ANS: ZERO 14. WHICH TWO CONDITIONS IN A PL/SQL BLOCK CAUSE AN EXCEPTION ERROR TO OCCUR ? CHOOSE TWO ANS: SELECT STATEMENT DOES NOT RETURN A ROW SELECT STATEMENT RETURNS MORE THAN ONE ROW 15. YOU NEED TO CREATE A PL/SQL PROGRAME TO INSERT RECORD INTO EMPLOYEE TABLE WHICH BLCOK OF CODE SUCCESSFULLY USES THE INSERT COMMAND ANS: DECLARE V_HIREDAT DATE:= SYSDATE; BEGIN INSERT INTO EMP (EMPNO,ENAME,HIREDATE) VALUES (EMPNO_SEQUENCE.NEXTVAL,?NAME?V_HIREDATE,&DEPTNO); END; EVALUATE THIS PL/SQL BLOCK 16. EVALUATE THIS PL/SQL BLOCK BEGIN FOR I IN 1..10 LOOP IF I=4 OR I=6 THEN NULL; ELSE INSERT INTO TEST(RESULT) VALUES(1); END; COMMIT; END LOOP; ROLL BACK; END; HOW MANY VALUES WILL BE INSERTED INTO THE TEST TABLE ? ANS: 8 17. YOU ISSUE COMMAND CREATE PUBLIC SYNONYM EMP FOR ED_EMPLOYEE WHICH TASK HAS BEEN ACCOMPLISHED? ANS: THE NEED TO QUALIFY THE OBJECT VALUE WITH ITS SCHEME IS ELIMINATED FOR ALL USERS 18. IN WHICH ORDER DOES THE ORACLE SERVER EVALUATE CLAUSES? WHERE, GROUP BY, HAVING 19. YOU ATTEMPT TO QUERY TO THE DATABASE WITH COMMAND SELELECT DEPT_NO, AVG(MONTHS_BETWEEN(SYSDATE,HIRE_DATE)) FROM EMPLOYEE WHERE AVG(MONTHS_BETWEENS(SYSDATE,HIRE_DATE))>60 GROUP BY DEPT_NO ORDER BY AVG(MONTHS_BETWEEN(SYSDATE,HIRE)DATE) WHY DOES THIS STATEMENT CAUSE AN ERROR ? ANS: A WHERE CLAUSE CAN NOT BE USED TO RESTRICT GRUPS. 20. THE PATH TABLE CONTAINS THESE COLUMNS ID NUMBER(7) PK COST NUMBER(7,2) PRODUCT_ID NUMBER(7) EVALUATE THESE SQL STATEMENT SELECT ROUND(MAX(COST),2), ROUND(MIN(COST),2), ROUND(SUM(COST),2), ROUND(AVG(COST),2) FROM PART; SELECT PRODUCT_ID, ROUND(MAX(COST),2), ROUND(MIN(COST),2), ROUND(SUM(COST),2), ROUND(AVG(COST),2) FROM PART GROUP BY PRODUCT_ID; HOW WILL THE RESULT DIFFER ANS: STATEMENT 1 WILL ONLY DISPLAY ONE ROW OF RESULTS STATEMENT CAN DISPLAY MORE THAN ONE. 21. IN WHICH SELECTION OF A PL/SQL BLOCK IS A USER DEFINED EXCEPTION RAISED? EXECUTABLE 22. EXAMINE THE CODE SET SERVER OUTPUT ON DECLARE V_CHAR_VAL VARCHAR2(100); BEGIN V_CHAR_VAL := ‘HELLO WORLD’; DBMS_OUTPUT.PUT_LINE (V_CHAR_VAL); END SET SERVER OUTPUT OFF THIS CODE IS STORED IN A SCRIPT TITLE NAME MYPROC.SQL. WHICH STATEMENT EXECUTES THE CODE IN THE SCRIPT TILE? ANS: START MYPROC.SQL 23. WHICH STATEMENT IS TRUE ABOUT NESTING BLOCKS ? ANS. A VARIABLE DEFINED IN THE OUTER BLOCK IS VISIBLE IN THE INNER BLOCK. 24. WHICH STATEMENT IS VALID WITHIN THE EXECUTABLE SECTION OF PL/SQL BLOCK ANS: SELECT ENAME, SAL INTO V_ENAME,V_SAL FROM EMP WHERE EMPNO = 101; 25. HOW DO YOU SEND THE OUTPUT OF YOUR SQL*PLUS SESSION TO A TEXT OPERATING SYSTEM FILE CALLED MYOUTPUT.LST? ANS. SPOOL MYOUTPUT.LST 26. THE PRDOUCT TABLE CONTAINS THESE COLUMNS ID NUMBER(9) PK COST NUMBER(7,2) SALE_PRICE NUMBER(7,2) MANAGEMENT HAS ASKED YOU TO CALCULATE THE NET REVENUE PER LIMIT FOR EACH PRODUCT IF THE COST OF EACH PRODUCT IS INCREASED BY 10% AND THE SALE PRICE OF EACH PRODUCT IS INCREASED BY 25% YOU ISSUE THE SQL STATEMENT SELECT ID, SAL_PRICE *1.25 ?COST *1.10 FROM PRODUCT; WHICH CONCLUSION CAN YOU DRAW FROM THE RESULT ? ANS.THE RESULTS PROVIDE MORE INFORMATION THAN MANAGEMENT REQUESTED 27. YOU WANT TO CREATE TO SHOW DIFFERENT JOBS IN EACH DEPARTMENT YOU DO NOT WANT TO DISPLAY ANY DUPLICATE ROLES IN THE REPORT WHICH SELECT SATEMENT DO YOU USE TO CREATE THE REPORT? ANS SELECT DISTINCT DEPTNO, JOB FROM EMP; 28. WHICH SELECT STATEMENT DISPLAYS EMPLOYEE NAMES, SALARY, DEPARTMENT NUMBERS AND AVERAGE SALARY IN THEIR DEPARTMENT? ANS. SELECT ENAME,SAL, DEPTNO, AVG(SAL) FROM EMP GROUP BY ENAM http://kao.xuezhishi.net/ITtest/Oracle/2007-06-17/27992.html
